Which of the following pairs of complexes are | vedclass

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(D) Molar conductivity depends on the number of ions produced in an aqueous solution.For $[CoBr(NH_3)_5]SO_4$,the dissociation is $[CoBr(NH_3)_5]SO_4

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$[CoBr(NH_3)_5]SO_4$ and $[Co(SO_4)(NH_3)_5]Br$

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(D) Molar conductivity depends on the number of ions produced in an aqueous solution.For $[CoBr(NH_3)_5]SO_4$,the dissociation is $[CoBr(NH_3)_5]SO_4 \rightarrow [CoBr(NH_3)_5]^{2+} + SO_4^{2-}$,which gives $2$ ions.For $[Co(SO_4)(NH_3)_5]Br$,the dissociation is $[Co(SO_4)(NH_3)_5]Br \rightarrow [Co(SO_4)(NH_3)_5]^+ + Br^-$,which gives $2$ ions.Wait,let us re-evaluate the options.Option $D$ involves ionization isomers where the ions produced are different ($SO_4^{2-}$ vs $Br^-$).Although both produce $2$ ions,the charge density and mobility of $SO_4^{2-}$ and $Br^-$ differ,leading to different molar conductivities.Therefore,the pair $[CoBr(NH_3)_5]SO_4$ and $[Co(SO_4)(NH_3)_5]Br$ are ionization isomers with different molar conductivities.

Which of the following pairs of complexes are isomeric with each other but their aqueous solutions exhibit different molar conductivities?

Similar Questions

The complex(es),which can exhibit the type of isomerism shown by $[Pt(NH_3)_2 Br_2]$,is(are) [en $= H_2 NCH_2 CH_2 NH_2$ ]
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